截取字符串替换成星号

阅读量：6647 次

发布时间：2019-06-25

本文共 1823 字，大约阅读时间需要 6 分钟。

1 public class TestDemo8 { 2  3     final static String STARS = "*******************************"; 4  5     public static void main(String[] args) { 6  7         String s = "(ADDRESS = (PROTOCOL = TCP)(HOST = 192.168.1.217)(PORT = 1521))"; 8           int beginIndex = s.indexOf("H"); 9           int endIndex = s.lastIndexOf("7");10           String news = s.substring(beginIndex, endIndex+1);11           12           System.out.println("s..." + s);13           System.out.println("beginIndex..." + beginIndex);14           System.out.println("endIndex..." + endIndex);15           System.out.println("news..." + news);16          18         System.out.println("getEmail..."+getEmail("liudehua@126.com"));    20     }21     22     public static String getEmail(String email){23         if(email == null)24             ;// error25         String[] emailParts = email.split("@");26         if(emailParts.length != 2)27             ;// 格式错误28         int len = emailParts[0].length();29         String char1 = emailParts[0].substring(0, 1);30         String char2 = emailParts[0].substring(len-1, len);31      // String char3 = STARS.substring(0, len - 2);  // 截取中间字符串位数32         String char3 = "***";33         34         System.out.println("1..." + emailParts[0]);  // liudehua35         System.out.println("2..." + emailParts[1]);  // 126.com36         System.out.println("char1..." + char1);  // l37         System.out.println("char2..." + char2);  // a38         39         return char1+char3+char2+"@"+emailParts[1];40     }41 42 } 输出结果如下：

s...(ADDRESS = (PROTOCOL = TCP)(HOST = 192.168.1.217)(PORT = 1521))

beginIndex...28

endIndex...47

news...HOST = 192.168.1.217

1...liudehua

2...126.com

char1...l

char2...a

getEmail...l***a@126.com